Posted by Ashley on .
Consider the reaction
3Fe(s) + 4H2O(g) ¨ 4H2(g) + Fe3O4(s).
If the volume of the container is reduced,
1. more Fe(s) is produced.
2. no change occurs.
3. more H2O(g) is produced.
4. more H2(g) is produced.
5. the equilibrium constant increases.
Le Chatelier's Principle says that a system in equilibrium will try to undo what we do to it. When volume is reduced that means pressure must be increased so the system will shift to the side with the fewer mols of gas. In this reaction there are 4 mols gas on the left and 4 mols gas on the right; therefore, no change occurs.