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March 29, 2015

March 29, 2015

Posted by **Jacob** on Wednesday, February 27, 2013 at 7:08pm.

Determine the constants a and b such that f has a relative maximum at x = 2 and the relative maximum value is 13.

- Applied Calculus -
**Steve**, Thursday, February 28, 2013 at 12:23amf'(x) = -2x+a

if f'=0 at x=2, then a=4

f(x) = -x^2 + 4x + b

f(2) = 13 = -4+8+b

b=5

f(x) = -x^2 + 4x + 5 = -(x+1)(x-5)

vertex is at x=(5-1)/2 = 2 as desired

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