George walks 3 km on Monday and 4 km of Tuesday and 2.5 km on Thursday . On Monday, he walked 25 mins., Tuesday 40 mins., and Thursday 30 mins. What is his average speed?

t=
D=

total distance: 3+4+2.5 = 9.5 km

total time: 25+40+30 = 95 min

9.5km/95min = 0.1km/min = 6km/hr

so 6km/hr is the answer??

Thanks Steve I understand

To find George's average speed, we need to first calculate the total distance he walked and the total time he took.

First, let's add up the distances:
George walked 3 km on Monday, 4 km on Tuesday, and 2.5 km on Thursday. So the total distance is:
3 km + 4 km + 2.5 km = 9.5 km.

Next, let's add up the times:
On Monday, George took 25 minutes.
On Tuesday, George took 40 minutes.
On Thursday, George took 30 minutes.
So the total time is:
25 minutes + 40 minutes + 30 minutes = 95 minutes.

Now, we can calculate the average speed using the formula:
Average speed (v) = Total distance (D) / Total time (t).

Plugging in the values, we have:
Average speed (v) = 9.5 km / 95 minutes

However, it is common practice to have the speed expressed in km/h, so we need to convert the time from minutes to hours.

Since there are 60 minutes in an hour, we divide the total time by 60 to convert it to hours:
95 minutes / 60 = 1.58 hours.

Now, we can calculate the average speed:
Average speed (v) = 9.5 km / 1.58 hours.

Dividing 9.5 km by 1.58 hours, our final answer for George's average speed is approximately 6.01 km/h.