George walks 3 km on Monday and 4 km of Tuesday and 2.5 km on Thursday. On Monday, he walks 25 mins., Tuesday 40 mins., and Thursday 30 mins. What is his average speed?

d=
t=
help please

Add the speeds to get d.

Add the times to get t.

Thanks so you add 3+4+2.5=9.5 for distance.

25+40+30=95
9.5km/95min=0.1km/min=6 km/hr.
so 6km/hr is the answer to everything or this whole problem?

To find George's average speed, we need to calculate the total distance traveled and the total time taken.

First, let's calculate the total distance traveled. Add up the distances walked each day:
George walked 3 km on Monday + 4 km on Tuesday + 2.5 km on Thursday = 9.5 km.

Next, let's calculate the total time taken. Add up the time spent walking each day:
George spent 25 mins walking on Monday + 40 mins on Tuesday + 30 mins on Thursday = 95 mins.

Now we have the total distance (9.5 km) and the total time taken (95 mins).

But note that the average speed should be in km/h, so we need to convert minutes to hours.

Since there are 60 minutes in 1 hour, we can calculate the total time in hours by dividing 95 mins by 60:
95 mins ÷ 60 = 1.58 hours (approximately).

Now we have the total distance (9.5 km) and the total time in hours (1.58 hours).

To find the average speed, we use the formula: Average speed = Total distance / Total time.

Plugging in the values:
Average speed = 9.5 km / 1.58 hours ≈ 6.01 km/h.

Therefore, George's average speed is approximately 6.01 km/h.