Applied Calculus
posted by Jacob on .
Find the third derivative of the function:
g(t)=square root of 7t+5

g = (7t+5)^1/2
g' = 1/2 (7t+5)^1/2 * 7 = 7/2 (7t+5)^1/2
g'' = (7/2)(1/2)(7t+5)^3/2 (7) = 49/4 (7t+5)^3/2
g''' = (49/4)(3/2)(7t+5)^5/2 (7) = 1029/8 (7t+5)^5/2