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Applied Calculus

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Find the third derivative of the function:
g(t)=square root of 7t+5

  • Applied Calculus - ,

    g = (7t+5)^1/2
    g' = 1/2 (7t+5)^-1/2 * 7 = 7/2 (7t+5)^-1/2
    g'' = (7/2)(-1/2)(7t+5)^-3/2 (7) = -49/4 (7t+5)^-3/2
    g''' = (-49/4)(-3/2)(7t+5)^-5/2 (7) = 1029/8 (7t+5)^-5/2

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