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2Al(s)+3Cl2 = 2AlCl3
Limiting Reactant is Cl with 0.329mol.

What is the maximum mass of aluminum chloride that can be formed when reacting 30.0g of aluminum with 35.0g of chlorine?

  • Chemistry - ,

    35g of Al*(1mole of Cl/35.45g)= mole of Cl

    3 moles of Cl= 2 moles of AlCl3

    moles of Cl *(2 moles of AlCl3/3 moles of Cl)= moles of AlCl3

    moles of ALCl3 *(133.34 g of AlCl3/mol)= mass of AlCl3

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