Jim is 45 years old. He is 10 years older than 5 times his niece Carol. How old is Carol
5C + 10 = 45
5C = 35
C = 7
J = 45 Jims age
C = Carols age
Jim is 10 years older than 5 times his niece Carol
J = 45 = 5 C + 10
45 = 5 C + 10 Subtract 10 to both sides
45 - 10 = 5 C + 10 - 10
35 = 5 C Divide both sides by 5
35 / 5 = 5 C / 5
7 = C
Carol is 7 yo
To find out Carol's age, we need to first calculate the value of the expression "5 times Carol's age + 10" and then subtract it from Jim's age.
Let's assume Carol's age is "C."
According to the given information:
Jim's age is 45 years.
Jim is 10 years older than 5 times Carol's age.
So, "5 times Carol's age + 10" can be written as (5C + 10).
To find Carol's age, we'll use the formula: Jim's age - (5C + 10) = Carol's age.
Substituting the known values into the equation:
45 - (5C + 10) = C
Simplifying the equation:
45 - 5C - 10 = C
35 - 5C = C
Combining like terms:
35 = 6C
To solve for C, divide both sides of the equation by 6:
35/6 = C
Using division or a calculator, we find that C ≈ 5.83.
Since we're dealing with ages here, it's safe to assume that Carol's age is a whole number. Thus, Carol's age is approximately 6 years old.