find the line perpendicular and passes through (0,0) 5x-2y =10
what does RX mean in communication skill.
perpendicular to
5x-2y=10
2y=5x-10
x=2.5 x-2 slope is 2.5, so slope of line perpendicular is -1/2.5 or -2/5
y=-2/5 x + b but it goes through 0,0
0=-2/5 (0)+b so b = 0
equation of the line:
y=-2/5 x
Rx in communication skills? I don't know. In Communication (Electronics) Engineering, Rx and Tx are pins for transmit on, or Receive on, and it usually keys an electronic swithch. I doubt if that is what you mean.
To find the line that is perpendicular to the given line and passes through the point (0,0), we need to consider the slope of the given line.
The given line is in the form of Ax + By = C, where A, B, and C are constants. In this case, the equation is 5x - 2y = 10.
To find the slope of this line, we can rewrite the equation in slope-intercept form (y = mx + b).
5x - 2y = 10
-2y = -5x + 10
y = (5/2)x - 5
Now, we can see that the slope of this line is 5/2.
To find the slope of a line perpendicular to this line, we need to flip the sign and take the negative reciprocal. The negative reciprocal of 5/2 is -2/5.
So, the slope of the perpendicular line is -2/5.
Using the point-slope form of a line (y - y1 = m(x - x1)), where (x1, y1) is the given point (0,0) and m is the slope we found (-2/5), we can determine the equation of the line.
y - 0 = (-2/5)(x - 0)
y = (-2/5)x
Therefore, the equation of the line that is perpendicular to the given line and passes through the point (0,0) is y = (-2/5)x.