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March 28, 2017

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There are two equal chords AB and and CD of a circle whose centre is O , when produced meet at point E. prove that EB=ED and EA=EC

  • maths-Circles - ,

    This is clearly wrong. Suppose CD is a diameter of the circle and AB is any other chord. Then ED is the shortest distance from E to any point on the circle. ED≠EB

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