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December 22, 2014

December 22, 2014

Posted by **paige** on Tuesday, February 26, 2013 at 1:22pm.

an = an – 1 – n minus one over seven n; fifteeen over one hundred nintey nine

an = a sub n plus one over n squared plus three ; fifteen over one hundred nintey nine

an = n plus one over n squared plus three ; fifteen over one hundred nintey nine

an = n over n cubed minus one ; fifteen over one hundred nintey nine

- math -
**Steve**, Tuesday, February 26, 2013 at 2:53pmwhat's with all the words? We have perfectly good digit keys...

1/2, 3/7, 1/3, 5/19, 3/14, ...

Looks pretty random, but we know we are after something we can easily relate to n. What if we get the denominators steadily increasing? Rewrite the sequence as

2/4, 3/7, 4/12, 5/19, 6/28

So, now it's easy to see that

an = (n+1)/(n^2+3)

a11 = 12/124 = 3/31

Dunno quite what to make of all the verbage below that. Try using some symbols and asking a question.

- math -
**Bob**, Tuesday, February 18, 2014 at 11:48pmHahaha! Oh Steve you crack me up with all that verbage and question asking. Anyways the question said to find a14, NOT a11. a14 = 15/199. So out of the wordy answer choices Paige gave, the answers C.

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