A block of aluminum with a volume of 98.5 cm3 absorbs 67.4 J of heat. If its initial temperature was 32.5 °C, what is its final temperature? (density of aluminum = 2.70 g/cm3)

I do not understand how to get the answer

Use density to find mass; i.e., mass = volume x density.

Then q = mass Al x specific heat Al x (Tfial-Tinitial)

To solve this problem, you need to use the formula:

Q = mcΔT

Where:
Q is the heat absorbed (in Joules)
m is the mass of the aluminum block (in grams)
c is the specific heat capacity of aluminum (in J/g°C)
ΔT is the change in temperature (in °C)

To find the mass of the aluminum block, you need to use its volume and density. The formula for density is:

density = mass / volume

Rearranging the formula, you can find the mass:

mass = density * volume

Now you have the mass and can proceed with the calculation.

1. Calculate the mass of the aluminum block:
mass = density * volume
mass = 2.70 g/cm3 * 98.5 cm3

2. Calculate the heat absorbed:
Q = mcΔT
67.4 J = mass * specific heat capacity * ΔT

3. Rearrange the equation to solve for ΔT:
ΔT = Q / (mass * specific heat capacity)

4. Calculate the change in temperature:
ΔT = 67.4 J / (mass * specific heat capacity)

Once you have ΔT, you can calculate the final temperature by adding the change in temperature to the initial temperature:

final temperature = initial temperature + ΔT

Now you can substitute the known values and calculate the final temperature.