A block of aluminum with a volume of 98.5 cm3 absorbs 67.4 J of heat. If its initial temperature was 32.5 °C, what is its final temperature? (density of aluminum = 2.70 g/cm3)

I do not understand how to get the answer

To solve this question, we can use the formula for heat transfer:

Q = mcΔT

Where:
Q is the amount of heat absorbed or transferred
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature

Since we are given the volume of the aluminum block, we need to find its mass. We can do this by multiplying the volume by the density:

Mass = Volume × Density

Now, let's calculate the mass of the aluminum block:

Mass = 98.5 cm^3 × 2.70 g/cm^3

The units of cm^3 will cancel out, leaving us with the mass in grams.

Next, we need to convert the mass from grams to kilograms by dividing it by 1000, as 1 kilogram is equal to 1000 grams.

After finding the mass in kilograms, we can rearrange the heat transfer formula to solve for ΔT:

ΔT = Q / (mc)

Given that Q = 67.4 J, the initial temperature is 32.5 °C, and the specific heat capacity of aluminum is approximately 900 J/kg°C, we can substitute these values into the formula:

ΔT = 67.4 J / (mass × c)

Finally, we can substitute the calculated mass and the known specific heat capacity of aluminum into the equation to find the change in temperature. Adding this change to the initial temperature will give us the final temperature.