How many btu's are absorbed when100 lbs of water is heated from 100f to200f
To calculate the BTUs absorbed when heating water, you can use the following formula:
Q = mcΔT
Where:
Q = Energy (BTUs)
m = Mass of the material (in pounds)
c = Specific Heat Capacity of the material (BTU/lb°F)
ΔT = Change in temperature (in °F)
In this case, you need to calculate the amount of BTUs absorbed when 100 lbs of water is heated from 100°F to 200°F.
The specific heat capacity of water is approximately 1 BTU/lb°F.
So, plugging the values into the formula:
Q = 100 lbs * 1 BTU/lb°F * (200°F - 100°F)
Calculating further:
Q = 100 lbs * 1 BTU/lb°F * 100°F
Q = 10,000 BTUs
Therefore, when heating 100 lbs of water from 100°F to 200°F, approximately 10,000 BTUs of energy are absorbed.