Post a New Question


posted by on .

find the theoreticval value of the period of a pendulum of length 0.9 meters located on the surface of the earth.

  • science - ,

    T^2 = 4*pi^2(L/g).
    T^2 = 4*9.86(0.9/9.81) = 3.62
    T = 1.9 s.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question