Post a New Question
posted by princess on Tuesday, February 26, 2013 at 10:18am.
find the theoreticval value of the period of a pendulum of length 0.9 meters located on the surface of the earth.
T^2 = 4*pi^2(L/g). T^2 = 4*9.86(0.9/9.81) = 3.62 T = 1.9 s.
More Related Questions