7750 Joules of energy is added to a 325 grams stone at 24.0 degrees centigrade. The temperature increases by 75.0 degrees centigrade. What is the specific heat of the stone?

To find the specific heat of the stone, we can use the equation:

Q = m * c * ΔT

Where:
Q = Energy added to the stone (in Joules)
m = Mass of the stone (in grams)
c = Specific heat of the stone (in J/g°C)
ΔT = Change in temperature of the stone (in °C)

In this case, the energy added to the stone is 7750 Joules, the mass of the stone is 325 grams, and the change in temperature is 75.0 degrees Celsius.

Substituting the given values into the equation, we have:

7750 J = 325 g * c * 75.0 °C

To find the value of c, we can rearrange the equation to solve for c:

c = 7750 J / (325 g * 75.0 °C)

Now, we can calculate the specific heat of the stone:

c = 0.321 J/g°C

Therefore, the specific heat of the stone is approximately 0.321 J/g°C.