What is the total capacitance of capacitors connected in series, C1=25F, C2=125F ? Round result to whole number.

just as with resistors in parallel,

1/C = 1/C1 + 1/C2

To find the total capacitance of capacitors connected in series, you need to use the formula:

1/C_total = 1/C1 + 1/C2 + ...

In this case, you have two capacitors connected in series, so the formula becomes:

1/C_total = 1/C1 + 1/C2

Now, substitute the given values:

1/C_total = 1/25 + 1/125

To add these fractions, the denominators must be the same, so we need to find a common denominator:

1/C_total = 5/125 + 1/125

Now add the fractions:

1/C_total = 6/125

To solve for C_total, take the reciprocal of both sides:

C_total = 125/6

Rounding this result to the nearest whole number, the total capacitance is approximately 21 Farads.