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March 1, 2015

Posted by **Taldil** on Tuesday, February 26, 2013 at 6:07am.

- Maths -
**Knights**, Tuesday, February 26, 2013 at 9:06amUh....I can't read it...

- Maths -
**Taldil**, Tuesday, February 26, 2013 at 1:37pmHi, sorry, the differential equation is:

x^3+(y+1)^2 dy/dx=0

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