Posted by **Hardwell** on Tuesday, February 26, 2013 at 5:08am.

f(x)=2x2−146x+c has 2 roots that are positive prime numbers. What is c?

- math -
**Steve**, Tuesday, February 26, 2013 at 5:29am
you know the factors are

(x-a)(2x-b)

where 2a+b=146

b must be even, so b=2k

a+k = 73

so, try

a=71 k=2

f(x) = (x-71)(2x-4) c=284

For any other smaller value of a, k must be even, so the above is the only solution

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