math
posted by Hardwell on .
f(x)=2x2−146x+c has 2 roots that are positive prime numbers. What is c?

you know the factors are
(xa)(2xb)
where 2a+b=146
b must be even, so b=2k
a+k = 73
so, try
a=71 k=2
f(x) = (x71)(2x4) c=284
For any other smaller value of a, k must be even, so the above is the only solution