f(x)=2x2−146x+c has 2 roots that are positive prime numbers. What is c?
you know the factors are
(x-a)(2x-b)
where 2a+b=146
b must be even, so b=2k
a+k = 73
so, try
a=71 k=2
f(x) = (x-71)(2x-4) c=284
For any other smaller value of a, k must be even, so the above is the only solution