Posted by Jeconiah on Tuesday, February 26, 2013 at 4:46am.
4a^2+9b^2+25c^212ab+20ac30bc divided by 2a3b+5c.

Algebra please help me!  Steve, Tuesday, February 26, 2013 at 9:50am
As I showed earlier,
4a^2 + 9b^2 + 25c^2  12ab + 20ac  30bc
= (2a3b+5c)^2
So, divide and you get 2a3b+5c