Posted by **angah** on Tuesday, February 26, 2013 at 4:15am.

by using method of undetermined coefficients

d^2y/dx^2 -5 dy/dx+6y=xe^x

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March 23, 2017
Posted by **angah** on Tuesday, February 26, 2013 at 4:15am.

by using method of undetermined coefficients

d^2y/dx^2 -5 dy/dx+6y=xe^x

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