Monday

September 1, 2014

September 1, 2014

Posted by **yuia** on Monday, February 25, 2013 at 11:43pm.

- pre-calculus -
**Steve**, Tuesday, February 26, 2013 at 12:39amIf the tangent hits the circle at (h,k)

it has length

L^2 + 1 = 16

L = sqrt(15)

h^2 + k^2 = 1

(4+h)^2 + k^2 = 15

Solve for h,k, and the slope is

k/(4+h)

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