1.)A 0.5 kg hockey puck moving at 35 m/s hits a straw bale, stopping in 1 s.
a) What impulse is delivered to the ball?
b) What force is exerted on the puck?
2.) A racing car with a mass of 1400 kg hits a slick spot and crashes head-on into a concrete wall at 50 m/s, coming to a halt in 0.8 s.
a) What is the change in momentum?
b) What is the impulse
c)What force is exerted on the car?
3.) An ambulance weighing 3000 kg comes racing to the rescue, hits the same slick spot, and then collides with a padded part of the wall at 50 m/s, coming to a halt in 2 s.
a) What is the change in momentum?
b) What is the impulse
c)What force is exerted on the ambulance?
d) How this answer differ from the problem above??
>>FORMULA'S<<
P=w/t
P= energy/time
P=mad/t
P= Fd/t
Ft=mvf-mvi
To solve these problems, we'll need to use the formulas related to momentum, impulse, and force. Let's break down each question step-by-step and explain how to find the answers.
1) For a 0.5 kg hockey puck moving at 35 m/s hitting a straw bale and stopping in 1 s:
a) The impulse delivered to the puck can be found using the formula P = m * Δv, where P is the impulse, m is the mass, and Δv is the change in velocity.
So, P = 0.5 kg * (0 m/s - 35 m/s) = -17.5 kg*m/s.
b) The force exerted on the puck can be found using the formula F = P / t, where F is the force and t is the time.
So, F = -17.5 kg*m/s / 1 s = -17.5 N (since force is a vector quantity, the negative sign indicates the force is in the opposite direction of motion).
2) For a racing car with a mass of 1400 kg crashing into a concrete wall at 50 m/s and coming to a halt in 0.8 s:
a) The change in momentum can be found using the formula Δp = m * Δv, where Δp is the change in momentum, m is the mass, and Δv is the change in velocity.
So, Δp = 1400 kg * (0 m/s - 50 m/s) = -70,000 kg*m/s.
b) The impulse can be calculated using the formula P = m * Δv, where P is the impulse, m is the mass, and Δv is the change in velocity.
So, P = 1400 kg * (0 m/s - 50 m/s) = -70,000 kg*m/s.
c) The force exerted on the car can be found using the formula F = P / t, where F is the force and t is the time.
So, F = -70,000 kg*m/s / 0.8 s = -87,500 N (note that the negative sign indicates the force is in the opposite direction of motion).
3) For an ambulance weighing 3000 kg crashing into a padded part of the wall at 50 m/s and coming to a halt in 2 s:
a) The change in momentum can be calculated using the formula Δp = m * Δv, where Δp is the change in momentum, m is the mass, and Δv is the change in velocity.
So, Δp = 3000 kg * (0 m/s - 50 m/s) = -150,000 kg*m/s.
b) The impulse can be found using the formula P = m * Δv, where P is the impulse, m is the mass, and Δv is the change in velocity.
So, P = 3000 kg * (0 m/s - 50 m/s) = -150,000 kg*m/s.
c) The force exerted on the ambulance can be calculated using the formula F = P / t, where F is the force and t is the time.
So, F = -150,000 kg*m/s / 2 s = -75,000 N (note that the negative sign indicates the force is in the opposite direction of motion).
d) The answer for the force exerted on the ambulance is the same as the previous problem (b), but the change in momentum and impulse are different due to the difference in mass, time, and velocity of the objects involved in the collision.