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March 30, 2015

March 30, 2015

Posted by **deq** on Monday, February 25, 2013 at 2:19am.

- differential equation -
**Damon**, Monday, February 25, 2013 at 3:39amdP/dt = .05 P

dP/P = .05 dt

ln P = .05 t

P = Pi e^.05t

if Pi = 1000 and t = 2

P = 1000 e^(.1) = 1105.17

4000 = 1000 e^.05t

e^.05 t = 4

.05 t = ln 4

t = 27.72 years

1000 for 1 year = 1051

2051 for year 2 = 2156

3156 for year 3 = 3318

4318 * e^.025 =4427

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