Posted by Valerie on Sunday, February 24, 2013 at 11:53pm.
A charge Q comes out of the battery.
That charge shows up on the top of the first C
It draws -Q from top of second, leaving + Q on second
That draws -Q from third, leaving +Q on top of #3
so
each capacitor has charge Q
C = Q/V
so
V1 = Q/C1
V2 = Q/C2
V3 = Q/C3
and
11 = V1+V2+V3
11 = Q (1/C1 + 1/C2 + 1/C3)
solve for Q
then V3 = Q/(31.8*01^-6)
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