A charge of 5 nC is located at

P(2,π/2,-3) and another charge of -10nC is situated at Q(5,π,0). Calculate the force exerted by one charge on the other. What is the nature of this force?

To calculate the force exerted by one charge on the other, you can use Coulomb's Law. Coulomb's Law states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:
F = (k * |q1 * q2|) / r^2

Where:
F is the force between the charges,
k is Coulomb's constant (9 * 10^9 N*m^2/C^2),
q1 and q2 are the charges, and
r is the distance between the charges.

In this case, q1 = 5 nC (positive charge) and q2 = -10 nC (negative charge).

First, let's calculate the distance between the charges using the distance formula:
r = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

Using the coordinates P(2, π/2, -3) and Q(5, π, 0), we have:
x1 = 2, y1 = π/2, z1 = -3,
x2 = 5, y2 = π, z2 = 0.

Plugging these values into the distance formula, we get:
r = √((5 - 2)^2 + (π - π/2)^2 + (0 - (-3))^2)
= √(3^2 + (π/2)^2 + 3^2)
= √(9 + (π/2)^2 + 9)
= √(18 + (π/2)^2)

Now, substitute the values into Coulomb's Law:
F = (k * |5 nC * -10 nC|) / (√(18 + (π/2)^2))^2

Calculating the magnitude of the charges:
|5 nC * -10 nC| = |-50 nC^2| = 50 nC^2

Plugging these values into Coulomb's Law:
F = (9 * 10^9 N*m^2/C^2 * 50 nC^2) / (√(18 + (π/2)^2))^2

Simplifying further will give you the magnitude of the force exerted by one charge on the other.

Regarding the nature of the force, since one charge is positive (5 nC) and the other charge is negative (-10 nC), the force will be attractive. Positive and negative charges attract each other.