Monday

September 1, 2014

September 1, 2014

Posted by **Brian** on Sunday, February 24, 2013 at 10:14pm.

I found N'(t)=(ae^-(bx))+axe^-(bx)

and i figure a=6M*.05=300000, but i cannot find the %population after 5 days. any help would be awesome, Thanks in advance!

- Calculus I, differentiation -
**Steve**, Monday, February 25, 2013 at 3:18pmN(t) = a(1 - e^-kt)

After 1 day, t=1, and we have

.05a = (1 - e^-k)

.05 = 1 - e^-k

0.95 = e^-k

k = -ln 0.95 = 0.0513

so,

N(t) = a(1 - e^-0.0513t)

So, by the end of day 5,

N(5) = a(1 - e^-.2565) = .226a = 22.6%

have heard the rumor

**Related Questions**

Calculus - The number, N, of people who have heard a rumor spread by mass media ...

Math - The number, N, of people who have heard a rumor spread by mass media by ...

Calculus - N(t) = 650/1+649 e^−0.5 t (b) How many people will have heard ...

Math - I can't calculate 1 as the answer given to the following problem. I keep ...

calculus - The rate at which a rumor spreads through an Alpine village of 400 ...

math - Could u help me with this question. The number, N, of people who have ...

biology - Given the part of the molecule shown below, can the underlined atom ...

Grade 12 Calculus - Evaluate each of the following. Show all your calculations...

calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...

calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...