What is the gram formula mass of NaC2H3O2 multiplied by 10H2O
You are greatly in error in your terms.
NaC2H3O2.10H2O the 10H20 is not multiplied, it is added to get the total formula mass. Water of hydration is often written in formulas with a separation sign from the main formula as an "addon", indicated the water is physically attached in the crystal. Physically, as opposed to chemically.
To calculate the gram formula mass of a compound, we need to determine the molar mass of each element in the compound and then add them up.
First, let's calculate the molar mass of each element in NaC2H3O2:
- Na (sodium) has a molar mass of approximately 22.99 g/mol.
- C (carbon) has a molar mass of approximately 12.01 g/mol.
- H (hydrogen) has a molar mass of approximately 1.01 g/mol.
- O (oxygen) has a molar mass of approximately 16.00 g/mol.
For NaC2H3O2, we have:
1 Na x 22.99 g/mol = 22.99 g/mol
2 C x 12.01 g/mol = 24.02 g/mol
3 H x 1.01 g/mol = 3.03 g/mol
2 O x 16.00 g/mol = 32.00 g/mol
Now, let's calculate the molar mass of the water molecules (H2O). Since there are 10 water molecules, we multiply the molar mass of water by 10:
10 H2O x 2 H x 1.01 g/mol = 20.20 g/mol
10 H2O x 1 O x 16.00 g/mol = 160.00 g/mol
Finally, we add the molar masses of NaC2H3O2 and 10H2O:
Gram formula mass = Mass of NaC2H3O2 + Mass of 10H2O
Gram formula mass = (22.99 g/mol + 24.02 g/mol + 3.03 g/mol + 32.00 g/mol) + (20.20 g/mol + 160.00 g/mol)
Calculating the sum of these molar masses gives us the gram formula mass of NaC2H3O2 multiplied by 10H2O.