Posted by **Anonymous** on Sunday, February 24, 2013 at 6:15pm.

If a rocket is propelled upward from ground level, it's height in meters after t seconds is given by h=-9.8t^2+88.2t. During what interval of time will the rocket be higher than 137.2m?

h=9.8t^2+ 88.2t

I divided both sides by -9.8 which gave me

t^2=-9

But I can't remember what step is next please help. Thanks in advance:-)

- algebra -
**MathGuru**, Monday, February 25, 2013 at 5:04pm
The equation:

137.2 = -9.8t^2 + 88.2t

Divide both sides by -9.8 (whatever operation you do to one side of an equation you must do to the other side as well):

(137.2)/-9.8 = (-9.8t^2 + 88.2t)/-9.8

-14 = t^2 - 9

Set the equation equal to 0:

0 = t^2 - 9 + 14

Try to factor:

0 = (t - 7)(t - 2)

Set the factors equal to 0:

t - 7 = 0

t - 2 = 0

Therefore, the two solutions are t = 2 and t = 7.

Interval: 2 < t < 7

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