Posted by **Jilian** on Sunday, February 24, 2013 at 5:15pm.

The equation of motion of a particle is s= 2y^3 - 7t^2 + 4t +1 where s is in meters and t is in seconds

a) Find the velocity and acceleration as functions of t.

b) Find the acceleration after 1 second.

- TYPO ? -
**Damon**, Sunday, February 24, 2013 at 5:36pm
are you sure that is 2y^3 and not 2 t^3 ?

2 y^3 is all right, but unusual and probably not intended.

- Calculus -
**Damon**, Sunday, February 24, 2013 at 5:39pm
If as typed, the 2y^3 has nothing to do with the velocity and acceleration

v =ds/dt = -14 t + 4

a = dv/dt = -14

If as I kind of have a hunch you mean

v = 6 t^2 - 14 t + 4

a = 12 t - 14

- Calculus -
**Jilian**, Sunday, February 24, 2013 at 6:00pm
it was 2 t^3

Thanks

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