Saturday

March 28, 2015

March 28, 2015

Posted by **Jilian** on Sunday, February 24, 2013 at 5:15pm.

a) Find the velocity and acceleration as functions of t.

b) Find the acceleration after 1 second.

- TYPO ? -
**Damon**, Sunday, February 24, 2013 at 5:36pmare you sure that is 2y^3 and not 2 t^3 ?

2 y^3 is all right, but unusual and probably not intended.

- Calculus -
**Damon**, Sunday, February 24, 2013 at 5:39pmIf as typed, the 2y^3 has nothing to do with the velocity and acceleration

v =ds/dt = -14 t + 4

a = dv/dt = -14

If as I kind of have a hunch you mean

v = 6 t^2 - 14 t + 4

a = 12 t - 14

- Calculus -
**Jilian**, Sunday, February 24, 2013 at 6:00pmit was 2 t^3

Thanks

**Answer this Question**

**Related Questions**

calculus - THe equation of motion of a particle is s = t^3 - 3t, where s is in ...

Calculus - The equation of motion of a particle is s=4t^3−7t, where s is ...

Calculus - The displacement (in meters) of a particle moving in a straight line ...

calculus - the equation of motion is given for a particle, where s is in meters ...

calculus - A particle moves along a straight line with equation of motion s = f(...

Calculus - A particle moves on a vertical line. Its position, s, in metres at t ...

Math - The displacement (in meters) of a particle moving in a straight line is ...

Calculus - The position of a particle moving on a horizontal line is given by s(...

calculus - the displacement (in meter) of a particle moving in a straight line ...

calculus - If an equation of motion of a particle is given by s(t)= Acos(ùt...