Saturday

April 19, 2014

April 19, 2014

Posted by **Jeannie** on Sunday, February 24, 2013 at 12:23pm.

- Algebra II -
**Steve**, Sunday, February 24, 2013 at 4:49pmthe height h at time t is

h(t) = 21 + 19t - 4.9t^2

so, plug in h=11 and solve for t:

11 = 21 + 19t - 4.9t^2

t ~= 4.35 sec

- Algebra II -
**Jeannie**, Sunday, February 24, 2013 at 5:28pm5.93

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