Wednesday
October 1, 2014

Homework Help: Physics

Posted by Meder on Sunday, February 24, 2013 at 12:12pm.

A 6.40 kg block rests on a 12.5 kg block as shown in the diagram.
The interface between the lower mass and the table is frictionless, but
there is friction (static friction μS and kinetic friction μK) between the two
blocks. A horizontal force F
r
acts on the UPPER block and causes both
blocks to accelerate. The acceleration of both blocks when they begin to
slip is 2.0 2 s
m .
(i) Calculate the force F at the time when the blocks start to slip.
6.40 kg
12.5 kg
F
(ii) Calculate the coefficient of static friction μS.

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