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July 30, 2014

July 30, 2014

Posted by **Kristien** on Sunday, February 24, 2013 at 6:37am.

tanA/secA+1 = secA-1/tanA

Can u please explainit to me step by step?

I greatly appreciate your help! Thanks:)

- Math -
**Steve**, Sunday, February 24, 2013 at 6:51amThis is exactly like the one with (1-sin)/cos

The identity tan^2 = sec^1 - 1 should help.

- Math -
**Kristien**, Sunday, February 24, 2013 at 7:04amwe never learned this identity

at school...is there any basio other identity thtwould help bcz im sure tht since we neverlearned this identity in class he wont mark it right on a test..

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