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March 1, 2015

March 1, 2015

Posted by **Jeremy** on Saturday, February 23, 2013 at 11:51pm.

y^2 = x^3 (2-x) (1,1)

- Calculus -
**Steve**, Sunday, February 24, 2013 at 6:37amy' = 3x^2 (2-x) - x^3

y'(1) = 3(1) - 1 = 2

so, now yu have a slope and a point:

y-1 = 2(x-1)

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