Ammonia is composed of hydrogen and nitrogen in a ratio of 9.33 g of nitrogen to 2.00 g of hydrogen. If 2.19 g of nitrogen combined completely with hydrogen to form ammonia, what mass (g) of ammonia would be formed?

9.33N2 + 2.00 H2 = 11.33 total.

11.33 x (2.19/2.00) = ?

To find the mass of ammonia formed, we need to determine the ratio of nitrogen to hydrogen in ammonia and then use that ratio to calculate the mass.

Given:
Mass of nitrogen (N₂) = 2.19 g
Mass of hydrogen (H₂) = 2.00 g

From the given information, the ratio of nitrogen to hydrogen in ammonia is 9.33 g of nitrogen to 2.00 g of hydrogen.

Now, let's calculate the mass of ammonia formed:

1. Determine the molar mass of nitrogen (N₂) and hydrogen (H₂):

- Molar mass of nitrogen (N₂) = 14.01 g/mol (14.01 g/mole x 2 moles)
- Molar mass of hydrogen (H₂) = 1.01 g/mol (1.01 g/mole x 2 moles)

2. Calculate the molar ratio of nitrogen to hydrogen in ammonia:

- Molar ratio = Molar mass of nitrogen / Molar mass of hydrogen
= 14.01 g/mol / 1.01 g/mol
= 13.875

3. Now, we can use the molar ratio of nitrogen to hydrogen to calculate the mass of ammonia (NH₃) formed:

- Mass of ammonia (NH₃) = (Mass of nitrogen / Molar ratio) + Mass of hydrogen
= (2.19 g / 13.875) + 2.00 g
= 0.157 g + 2.00 g
= 2.157 g

Therefore, the mass of ammonia formed would be 2.157 g.

To find the mass of ammonia formed, we need to determine the ratio of nitrogen to ammonia, and then calculate based on the given mass of nitrogen.

1. Start by calculating the molar mass of nitrogen (N) and hydrogen (H). The molar mass of nitrogen is 14.01 g/mol, while the molar mass of hydrogen is 1.01 g/mol.

2. Use the given ratio of nitrogen to hydrogen (9.33 g of nitrogen to 2.00 g of hydrogen) to convert the mass of nitrogen to moles. Divide the mass of nitrogen by its molar mass:
moles of nitrogen = 2.19 g of nitrogen / 14.01 g/mol = 0.156 moles of nitrogen

3. Based on the balanced chemical equation for the formation of ammonia (NH3), we know that 1 mole of nitrogen reacts with 3 moles of hydrogen to form 2 moles of ammonia.

4. Using the molar ratio from the balanced chemical equation, calculate the moles of ammonia:
moles of ammonia = (0.156 moles of nitrogen) x (2 moles of ammonia / 1 mole of nitrogen) = 0.312 moles of ammonia

5. Finally, calculate the mass of ammonia formed by multiplying the moles of ammonia by its molar mass:
mass of ammonia = 0.312 moles of ammonia x 17.03 g/mol (molar mass of ammonia) = 5.32 g of ammonia

Therefore, 5.32 grams of ammonia would be formed when 2.19 grams of nitrogen combines completely with hydrogen.