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Calculus

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F(x) = (x^3 - x + 1)^4
f'(x)=

  • Calculus -

    Just use the chain rule

    d/dx (u^n) = n u^(n-1) du/dx
    so, we get

    4 (x^3-x+1)^3 * (3x^2-1)

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