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posted by Nelly on Saturday, February 23, 2013 at 12:10am.

F(x) = (x^3 - x + 1)^4 f'(x)=

Just use the chain rule d/dx (u^n) = n u^(n-1) du/dx so, we get 4 (x^3-x+1)^3 * (3x^2-1)

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