Monday
July 28, 2014

Homework Help: chemistry

Posted by Fai on Friday, February 22, 2013 at 11:57pm.

0.50g of a mixture of K2c03 and Li2c03 requires 30ml of a 0.25N hcl solution for neutralization. What is the percentage composition of the mixture?
The answer k2c03 96%
Li2c03 4%
K2c03 weight 138g/mol
138/2 = 69
Li2c03 weight 74g/mol
74/2 = 37
30ml x 0.25N = 7.5 / 1000
x= 0.0075

Who helps me to solve it for me
Please Bob

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