Posted by **Stephanie** on Friday, February 22, 2013 at 9:21pm.

I am confused on how solve this substitution problem

4y+3=3y+x

2x+4y=18

If you can, show work please (:

- Algebra -
**Alex**, Saturday, February 23, 2013 at 7:45am
I am pretty sure this goes like this

4y+3=3y+x (i)

2x+4y=18 (ii)

Rearrange (i) so that x=4y+3-3y

Take (ii) and sub x

it will become 2(4y+3-3y)+4y= 18

2(y+3)+4y =18

2y+6+4y=18

6y+6=18

6y=18-6

6y=12

y=12/6

y=2 (iii)

Now use what you found for y in (iii) and sub in the (ii or i to get x)

lets take (i) 4y+3=3y+x

from (iii) 4(2)+3=3(2)+x

11=6+x

x= 11-6

x=5

let me know if that's clear enough

- Algebra -
**Stephanie**, Saturday, February 23, 2013 at 8:09am
Yes that is thank you so much (:

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