Algebra
posted by Stephanie .
I am confused on how solve this substitution problem
4y+3=3y+x
2x+4y=18
If you can, show work please (:

I am pretty sure this goes like this
4y+3=3y+x (i)
2x+4y=18 (ii)
Rearrange (i) so that x=4y+33y
Take (ii) and sub x
it will become 2(4y+33y)+4y= 18
2(y+3)+4y =18
2y+6+4y=18
6y+6=18
6y=186
6y=12
y=12/6
y=2 (iii)
Now use what you found for y in (iii) and sub in the (ii or i to get x)
lets take (i) 4y+3=3y+x
from (iii) 4(2)+3=3(2)+x
11=6+x
x= 116
x=5
let me know if that's clear enough 
Yes that is thank you so much (: