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June 30, 2016
Posted by **Molly** on Friday, February 22, 2013 at 6:56pm.

- calculus -
**bobpursley**, Friday, February 22, 2013 at 7:31pmIs there a question here?

- calculus -
**Molly**, Friday, February 22, 2013 at 11:11pmSorry

y'= - calculus -
**Steve**, Saturday, February 23, 2013 at 5:02amjust use the quotient rule. If

y = u/v

y' = (vu'-uv')/v^2

y' = [(1+tanx)(cosx) - (sinx)(sec^2 x)]/(1+tanx)^2

= ((cosx - (sinx)(tan^2 x))/(1+tanx)^2