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posted by britnay on Friday, February 22, 2013 at 6:36pm.
if one of the zeros of y=x^2+bx+1 is 1 determine the value of b anyone understand this and can help me break it down
It means when y = 0 then x = 1 0 = 1^2 + b(1) + 1 0 = 1 + b + 1 Solve for b.
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