Posted by britnay on .
if one of the zeros of y=x^2+bx+1 is 1 determine the value of b
anyone understand this and can help me break it down

math 
JJ,
It means when y = 0 then x = 1
0 = 1^2 + b(1) + 1
0 = 1 + b + 1
Solve for b.