Posted by Need help really fast! on Friday, February 22, 2013 at 12:03pm.
An observer on a cliff 1000 dm above sea level sights two ships due east. the angles of depression of the ships are 44o and 32o. Find the distance between the ships.

Trigonometry  Steve, Friday, February 22, 2013 at 12:28pm
draw a diagram. If the near ship is at distance x from shore, and the ships are d apart, then
x = 1000 cot44°
x+d = 1000 cot32°
so, d = 1000(cot32° cot44°)
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