Posted by **Need help really fast!** on Friday, February 22, 2013 at 12:03pm.

An observer on a cliff 1000 dm above sea level sights two ships due east. the angles of depression of the ships are 44o and 32o. Find the distance between the ships.

- Trigonometry -
**Steve**, Friday, February 22, 2013 at 12:28pm
draw a diagram. If the near ship is at distance x from shore, and the ships are d apart, then

x = 1000 cot44°

x+d = 1000 cot32°

so, d = 1000(cot32°- cot44°)

## Answer this Question

## Related Questions

- Trigonometry - An observer in a lighthouse 350 feet above sea level observes two...
- math - an observer in a lighthouse 300 ft above sea level observes 2 ships ...
- geometry - the pilot of a plane flying 2000 meters above sea level observes two ...
- math - from a height of 40 m above sea level, two ships are traveling due west. ...
- maths - a person observed from the top of a light house which is 80 m above the ...
- angle - 1.) From the top of a lighthouse 52 metres high,the angles of depression...
- Trig - I have no idea how to do this problem From an airplane flying 2 ...
- maths - An airplane is flying at an altitude of 10,000m. The pilot sees two ...
- maths - Iam stuck with this question.Please anyone help me. An airplane is ...
- Advanced Maths (Vectors) AQA Level, please help? - Two ships, A and B st out ...