Posted by **Anonymous** on Friday, February 22, 2013 at 11:59am.

A circular swimming pool has a diameter of 14 m, the sides are 4 m high, and the depth of the water is 3.5 m. (The acceleration due to gravity is 9.8 and the density of water is 1000 .)

How much work (in Joules) is required to:

(a) pump all of the water over the side?

(b) pump all of the water out of an outlet 2 m over the side

- calculus -
**Damon**, Friday, February 22, 2013 at 1:08pm
If you are at all smart, none.

You siphon the water out.

However if you really want to lift it all to the top then the answer is the mass of water times height you lift it times gravity ( m g h )

Mass = m = pi (7)^2 (3.5)(1000) m^3

g = 9.8 m/s^2

h = 4 - (3.5)/2 = 2.25 m

so multiply and get Joules

for the second part use 2.25 + 2 = 4.25 for h

## Answer This Question

## Related Questions

- REALLY HARD CALCULUS PROBLEMMMM PLEASE HELP ME??? - A circular swimming pool has...
- Calculus - Suppose that water is pouring into a swimming pool in the shape of a ...
- calculus - Suppose that water is pouring into a swimming pool in the shape of a ...
- math - calculus - Suppose that water is pouring into a swimming pool in the ...
- physics - A circular swimming pool has a flat bottom and a 4.39 m diameter. It ...
- maths - A swimming pool has two identical sides in the shape of a trapezium. All...
- calculus - my circular swimming pool has a 29 foot diameter and is 8 feet tall. ...
- Math - A circular swimming pool is 4 feet deep and has a diameter of 15 feet. If...
- Math - Suppose that water is pouring into a swimming pool in the shape of a ...
- Physics - A 5/8 inch (inside) diameter garden hose is used to fill a round ...

More Related Questions