Posted by Jazz on Friday, February 22, 2013 at 10:53am.
Do you have numbers for this problem?
Last year, Joe had 10,000 to invest. He invested some of it in an account that paid 7% simple interest per year, and he invested the rest in an account that paid 9% simple interest per year. After one year, he received a total of $860 in interest. How much did he invest in each account?
(sorry bout that).
x = amount in the first account
y = amount in the second account.
total invested:
x + y = 10,000
since Interest = Principles times rate times time.
.07x + .08y = 860
Now, you work with those two equations.
I would multiply the bottom equation by 100 to get rid of the decimals.
x + y = 10000
7x + 8y = 86000
Now, you can solve this by using the substitution method or the addition method.
I probably would use the addition(also known as the elimination method.)
Multiply the top equation by -7 and solve for y. Once you have y, you can find x. Then be sure to check x and y in both equations.
where did you get .08 from?
Sorry.. the .08 is a typo. It should be .09
Which makes the equation 7x + 9y = 86000
it would be 7x+7y=70000? I dont know how to solve the two equations
it would be 7x+7y=70000? I dont know how to solve the two equations
it would be 7x+7y=70000? I dont know how to solve the two equations
I dont think I'm doing this right because i am getting HUGE numbers like 156,000
-7x -7y =70000
7x + 9y =86000
2y = 156000
divide by 2 and you get 7800 for y
so the other amount must be 2200.
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