Posted by Sammie on Friday, February 22, 2013 at 9:33am.
A ball is tossed from an upperstorey window of a building.The ball is given an initial velocity of 8 m/s at an angle of 20 degrees below the horizontal.it strikes the ground 3s later .(a) How far horizontally from the base of the building does the ball strike the ground? (b)Find the height from which the ball was thrown. (c) How long does it take the ball to reach a point 10.0m below the level of launching?

Physics urgent pls!  Henry, Sunday, February 24, 2013 at 7:43pm
Vo = 8 m/s. @ 20o = Initial velocity.
Xo = 8*cos20 = 7.52 m/s = Hor. comp.
Yo = 8*sin20 = 2.74 m/s = Ver. comp.
a. d = Xo * Tf = 7.52m/s * 3s.=22.56 m.
b. h = Yo*Tf + 0.5g*Tf^2.
h = 2.74*3 + 4.9*3^2 = 52.32 m.
c. h = Yo*t + 0.5g*t^2 = 10 m.
2.74t + 4.9t^2 = 10
4.9t^2 + 2.74t  10 = 0
Use Quad. Formula:
t = 1.18 s.

Physics urgent pls!  archie, Wednesday, June 19, 2013 at 7:42am
how did you get that 0.5g??

Physics urgent pls!  Anonymous, Thursday, September 25, 2014 at 12:18pm
in reply to "how did you get that 0.5g??":
0.5g= (1/2)(g)=(1/2)(9.8)
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