Thursday
March 23, 2017

Post a New Question

Posted by on Friday, February 22, 2013 at 9:27am.

A wooden crate weighs 780 lb. What force is needed to start the crate sliding on a wooden floor when the coefficient of starting friction is 0.40?

  • physics - , Sunday, February 24, 2013 at 3:57pm

    Mass = 780Lbs * 0.454kg/Lb = 354.1 kg.

    Wc = 354.1kg * 9.8N/kg = 3470. N.
    Fp = 3470*sin0 = 0. = Force parallel to floor.
    Fv = 3470*cos0 = 3470 N. = Force perpendicular to floor.

    Fs = u*Fv = 0.4 * 3470 = 1388 N. = Force
    of starting friction.

    Fap-Fp-Fs = m*a.
    Fap-0-1388 = m*0 = 0
    Fap = 1388 N. = Force applied.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question