Posted by Sammie on Friday, February 22, 2013 at 9:22am.
Vo = 45m/s @ 50o
Xo = 45*cos50 = 28.93 m/s.
Yo = 45*sin50 = 34.47 m/s.
a. Y^2 = Yo^2 + 2g*h.
h = (Y^2-Yo^2)/2g.
h = (0-(34.47)^2)/-19.6=60.6 m.=Max ht.
Y = Yo + g*t.
Tr = (Y-Yo)/g = (0-34.47)/-9.8=3.52 s.=
Rise time or time to reach max ht.
Xo*T = 150m
28.93*T = 150
T = 5.18 s. = Time in air.
Tf = 5.18 - 3.52 = 1.66 s.
h = hmax - 0.5g*t^2
h = 60.6 - 4.9*(1.66)^2=60.6-13.5=47.1
m above launching level.
d = Vo*t + 0.5g*t^2 = 47.1 m.
Vo*5.18 - 4.9*(5.18)^2 = 47.1
Vo*5.18 - 131.48 = 47.1
Vo*5.18 = 178.58
Vo = 34.47 m/s. = Initial velocity of the apple.
b. T = 0. Apple must be thrown at same time arrow is launched.
_
Related Questions
Physics help!! - An archer shoots an arrow with a velocity of 45 m/s at an angle...
Physics - Two archers shoot arrows in the same direction from the same place ...
Basic Physics - While standing on an open bed of a truck moving at 35 m/s, and ...
physics - an archer at the edge of a cliff fires an arrow from a height of 14.6 ...
physics - an archer at the edge of a cliff fires an arrow from a height of 14.6 ...
Physics Quick! - An archer shoots an arrow with a velocity of 49.5 m/s at an ...
Physics - An archer wishes to shoot an arrow at a target at eye level a distance...
physics - An archer shoots an arrow horizontally with an initial velocity of 100...
Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
Physics - An archer shoots an arrow that leaves the bow at an angle of 42 ...
For Further Reading