Posted by **Therese** on Friday, February 22, 2013 at 8:53am.

Out of 4 architects, 6 engineers and 9 electricians, how many ways can a group of 6 people be formed to attend a forum if:

a. there is an equal number of architects, engineers and electricians

b. two particular engineers cannot be in the committee?

c. there are at least 3 electricians?

- Math -
**JJ**, Friday, February 22, 2013 at 1:19pm
a. equal number of each

Combinations again..

architects 4!/(2!2!)

engineers 6!/(2!4!)

electricians 9!/(2!7!)

b. remove the 2 engineers from the choices which would leave 4 architechts, 4 engineers and 9 electricians Now, we have 17 to choose from to make a group of 6.

17!/(6! 11!)

- Math -
**Therese**, Friday, February 22, 2013 at 8:32pm
Thanks much :)

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