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January 26, 2015

January 26, 2015

Posted by **mary jackson** on Friday, February 22, 2013 at 5:57am.

- math -
**JJ**, Friday, February 22, 2013 at 9:23am4/16 getting a red the first time

No replacement

3/15 getting a red the second time

Multiply these probabilities together.

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