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July 31, 2014

July 31, 2014

Posted by **sandy** on Friday, February 22, 2013 at 2:13am.

- math -
**Lena**, Friday, February 22, 2013 at 2:22amSo 4 names went into the bowl.

If Sam is the first person selecting then the chances of him pulling out his name are 1/4. 1/4 as a percent is 25%.

The second person selecting, Pam, now only has 3 names left in the bowl. Therefore, the chances that Pam will select Sam are now 1/3. 1/3 as a percent is 33.33(repeating)%.

Does that make sense?

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