Posted by Dan on Friday, February 22, 2013 at 12:11am.
V = 190km/h @ 155o + 45km/h @ 15o.
X = 190*cos155 + 45*cos15=-128.73 km/h.
Y = 190*sin155 + 45*sin15=91.94 km/h.
tanAr = Y/X = 91.94/-128.73 = 0.71424
Ar = -35.53o = Reference angle.
A = -35.54 + 180 = 144.5o
V = X/cosA = -128.73/cos144.5=158.1 km/h
@ 144.5o, CCW.
Note: One student said that the book's
answer is 227 km/h @ 162.4o. Based on
the INFO given, that would be impossible
because:
1. The direction of the wind reduces
the speed of the plane.
2. The resultant direction would have to be less than 155o.
Related Questions
Honors Trig. - A plane is flying at a speed and direction of 550 mph, 25 degrees...
Physics - A plane is flying 25 degrees north of west at 190 km/h and encounters ...
Physics - An airplane flying at 82km/hr at 30 degrees east of north encounters a...
physics - It says, A plane travels 400 mi/h relative to the ground. There is a ...
physics - The accelerating force of the wind on a small 200-kg sailboat is 707 N...
Physics - A small plane is 150km south of the equator. The plane is flying at ...
My Friend Needs Help With a Calc Problem. - how does five degrees east of north ...
physics - An airplane is flying with a speed of 240 km/hr at an angle of 27 ...
trig - a plane is flying with airspeed of 140 mph and heading 280 degrees. The ...
Physics - a plane is flying due north at 155 mi/h and encounters a wind from the...
For Further Reading
