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April 20, 2014

April 20, 2014

Posted by **Dan** on Friday, February 22, 2013 at 12:11am.

- Physics -
**Henry**, Saturday, February 23, 2013 at 7:25pmV = 190km/h @ 155o + 45km/h @ 15o.

X = 190*cos155 + 45*cos15=-128.73 km/h.

Y = 190*sin155 + 45*sin15=91.94 km/h.

tanAr = Y/X = 91.94/-128.73 = 0.71424

Ar = -35.53o = Reference angle.

A = -35.54 + 180 = 144.5o

V = X/cosA = -128.73/cos144.5=158.1 km/h

@ 144.5o, CCW.

Note: One student said that the book's

answer is 227 km/h @ 162.4o. Based on

the INFO given, that would be impossible

because:

1. The direction of the wind reduces

the speed of the plane.

2. The resultant direction would have to be less than 155o.

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