At standard temperature, a gas has a volume
of 312 mL. The temperature is then increased
to 115◦C, and the pressure is held constant.
What is the new volume?
Answer in units of mL
(V1/T1) = (V2/T2)
Remember T must be in kelvin.
To determine the new volume, we need to apply Charles's Law, which states that the volume of a gas is directly proportional to its temperature, given a constant pressure. The mathematical expression for Charles's Law is:
V1 / T1 = V2 / T2
Where:
V1 = initial volume of the gas
T1 = initial temperature of the gas (in Kelvin)
V2 = final volume of the gas
T2 = final temperature of the gas (in Kelvin)
Now, let's solve the problem step by step:
1. Convert the given temperature to Kelvin:
115°C + 273.15 = 388.15 K
2. Plug the values into Charles's Law equation:
312 mL / T1 = V2 / 388.15 K
3. Re-arrange the equation to solve for V2:
V2 = (312 mL * 388.15 K) / T1
4. Substitute the value of T1 (standard temperature) which is 273.15 K:
V2 = (312 mL * 388.15 K) / 273.15 K
5. Calculate the new volume:
V2 = 441.92 mL (rounded to the nearest hundredth)
Therefore, the new volume of the gas, when the temperature is increased to 115°C, while keeping the pressure constant, is approximately 441.92 mL.